MATH SOLVE

5 months ago

Q:
# 1)Choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown. y = x - 8 y = -3x + 12 y = 3x - 24 y = - x - 4

Accepted Solution

A:

To find the equation for the line in slope-intercept form y= mx + b, perpendicular to the line shown and passing through (6, -6):

The slope of the blue line is the rise (change in y) divided by run (change in x)

Choosing two points on the line (0, -6) and (2,0)

Slope = (0 - (-6)) / (2 - 0) = 6 / 2 = 3

The slope of our perpendicular line will be the opposite inverse, so:

m = -1/3

We have the point (6, -6) so we can solve for b

y = mx + b

-6 = (-1/3)*6 + b

-6 = -2 + b

b = -4

We know that m= (-1/3) and b= -4, so:

y = (-1/3)x - 4

This is definitely the correct answer. None of the above answers describe the line that is perpendicular to the blue line and passes through (6, -6). Make sure you wrote the options down correctly.

The slope of the blue line is the rise (change in y) divided by run (change in x)

Choosing two points on the line (0, -6) and (2,0)

Slope = (0 - (-6)) / (2 - 0) = 6 / 2 = 3

The slope of our perpendicular line will be the opposite inverse, so:

m = -1/3

We have the point (6, -6) so we can solve for b

y = mx + b

-6 = (-1/3)*6 + b

-6 = -2 + b

b = -4

We know that m= (-1/3) and b= -4, so:

y = (-1/3)x - 4

This is definitely the correct answer. None of the above answers describe the line that is perpendicular to the blue line and passes through (6, -6). Make sure you wrote the options down correctly.